Display Date Dos Bat File

Hi, How do I obtain the yesterday date for MSDOS batch? I am curently doing the following which is faulty.

I am not sure how I can deduce the date correctly. Please advise. CM -------------------------- ---------- ---------- ---------- ---------- ---------- ---------- ---------- -- for /F 'tokens=1-4 delims=/- '%%a in ('date/T') do set DATE=%%d%%c%%b for /F 'tokens=1-4 delims=/- '%%a in ('date/T') do set /a DAY=%%b set /a YESTERDAY = DATE - 1 echo%DAY% if '%DAY%' == '1' ( set YESTERDAY=%DATE% )else ( set YESTERDAY = DATE - 1 ) echo%YESTERDAY%. Here's a batch file I developed to subtract any number of days from the current date.

Batch How To. Read File Properties. Many times we need to check a file's size, its last-modified date, its location, or we may require its fully qualified path in. South Africa Tomtom Maps. Format date and time in a. It is similar to Stack Overflow question How to append a date in batch files. Batch file to display Date and Time seprated.

It accepts a command line parameter of the number of days. The default is 1 day (yesterday): @echo off set yyyy= set $tok=1-3 for /f 'tokens=1 delims=.:/-, '%%u in ('date /t') do set $d1=%%u if '%$d1:~0,1%' GTR '9' set $tok=2-4 for /f 'tokens=%$tok% delims=.:/-, '%%u in ('date /t') do ( for /f 'skip=1 tokens=2-4 delims=/-,().'